210=2x^2+x

Solution for 210=2x^2+x equation:

210=2x^2+x

We move all terms to the left:

210-(2x^2+x)=0

We get rid of parentheses

-2x^2-x+210=0

We add all the numbers together, and all the variables

-2x^2-1x+210=0

a = -2; b = -1; c = +210;
Δ = b2-4ac
Δ = -12-4·(-2)·210
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-41}{2*-2}=\frac{-40}{-4}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+41}{2*-2}=\frac{42}{-4}
=-10+1/2
$